a = { 'name':'','id':'','college':'','major':''}
print(a)
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b = ['lisa','rita','ruby','winnie']
print(b)
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b = ['lisa','rita','ruby','winnie']
print(b)
#删除
b.remove('lisa')
print(b)
#增加
b.append('cindy')
print(b)
#修改
b[2]='rose'
print(b)
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b = ['lisa','rita','ruby','winnie']
print(b)
a = set(b)
print(a)
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a = {'x':7,'y':5,'z':9}
to_p = len(a)
print("总人数为:",to_p)
to_s = sum(a.values())
print("总分为:",to_s)
ave = to_s/to_p
print("平均分为:",ave)
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a = [69,52,99,77,43,97]
print([i for i in a if i<60])
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score = [68,98,54,39,65,76]
import random
y = int(random.randint(0,len(score)))
x = int(random.randint(0,y))
print(score[x:y])
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g = ((i*2) for i in range(10))
print(list(g))
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a = {}
str = '棋盘一共64个小格子,第一个格子放一粒米,第二个2粒米,第三个4粒米,第四个8粒米,以此类推一直把64个格子放满需要多少粒米?要求使用列表推导式和内置函数进行计算。'
for x in str:
if x in a :
a[x] += 1
else:
a[x] = 1
print(a)
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g = ((2**(i-1)) for i in range(1,64))
print(sum(g))
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实验次数 1次
报告字数 2978字
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